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(A) The given differential equation is $y''' + 2y'' + y' = 0$. The order of a differential equation is the order of the highest derivative present in

Vedclass · Accepted Answer

Order $3$,Degree $1$

Vedclass · Answer

(A) The given differential equation is $y''' + 2y'' + y' = 0$. The order of a differential equation is the order of the highest derivative present in the equation. Here,the highest derivative is $y'''$,which is the third derivative. Thus,the order is $3$. The degree of a differential equation is the power of the highest order derivative,provided the equation is a polynomial in derivatives. Here,the power of $y'''$ is $1$. Thus,the degree is $1$.

Determine the order and degree (if defined) of the differential equation $y''' + 2y'' + y' = 0$.

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