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(B) According to the Factor Theorem,$(x + 1)$ is a factor of $p(x)$ if and only if $p(-1) = 0$.Given $p(x) = x^{4} + x^{3} + x^{2} + x + 1$.Substituti

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No

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(B) According to the Factor Theorem,$(x + 1)$ is a factor of $p(x)$ if and only if $p(-1) = 0$.Given $p(x) = x^{4} + x^{3} + x^{2} + x + 1$.Substituting $x = -1$ into the polynomial:$p(-1) = (-1)^{4} + (-1)^{3} + (-1)^{2} + (-1) + 1$Calculating each term:$p(-1) = 1 - 1 + 1 - 1 + 1$Simplifying the expression:$p(-1) = 1$Since $p(-1) 
eq 0$,by the Factor Theorem,$(x + 1)$ is not a factor of the given polynomial.

Determine whether $(x + 1)$ is a factor of the polynomial $p(x) = x^{4} + x^{3} + x^{2} + x + 1$.

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