Differentiate sin left(cos left(x^{2}right)ri | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Let $y = \sin \left(\cos \left(x^{2}\right)\right).$ Using the chain rule,we differentiate with respect to $x$: $\frac{dy}{dx} = \frac{d}{dx} \left[ \

Vedclass · Accepted Answer

Vedclass · Answer

Let $y = \sin \left(\cos \left(x^{2}\right)\right).$
Using the chain rule,we differentiate with respect to $x$:
$\frac{dy}{dx} = \frac{d}{dx} \left[ \sin \left(\cos \left(x^{2}\right)\right) \right]$
$= \cos \left(\cos \left(x^{2}\right)\right) \cdot \frac{d}{dx} \left( \cos \left(x^{2}\right) \right)$
$= \cos \left(\cos \left(x^{2}\right)\right) \cdot \left( -\sin \left(x^{2}\right) \right) \cdot \frac{d}{dx} \left( x^{2} \right)$
$= \cos \left(\cos \left(x^{2}\right)\right) \cdot (-\sin \left(x^{2}\right)) \cdot (2x)$
$= -2x \sin \left(x^{2}\right) \cos \left(\cos \left(x^{2}\right)\right).$

Differentiate $\sin \left(\cos \left(x^{2}\right)\right)$ with respect to $x.$

Similar Questions

Let $f$ and $g$ be differentiable functions satisfying $g'(a) = 2$,$g(a) = b$,and $f \circ g = I$ (identity function). Then $f'(b)$ is equal to

Find the derivative: $\frac{d}{dx} \sqrt{x \sin x}$

$y=\log \left\{\left(\frac{1+x}{1-x}\right)^{1 / 4}\right\}-\frac{1}{2} \tan ^{-1}(x)$,then $\frac{d y}{d x}$ is equal to

If $2f(\sin x) + f(\cos x) = x,$ then $\frac{d}{dx} f(x)$ is

If $y = \cos^{-1}(\tanh x) + \sinh(\sin 6x)$, then $\frac{dy}{dx} =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module