Drift velocity V_d varies with the intensity | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The current $I$ in a conductor is given by $I = n e A v_d$,where $n$ is the number density of electrons,$e$ is the charge of an electron,$A$ is th

Vedclass · Accepted Answer

$V_d \propto E$

Vedclass · Answer

(A) The current $I$ in a conductor is given by $I = n e A v_d$,where $n$ is the number density of electrons,$e$ is the charge of an electron,$A$ is the cross-sectional area,and $v_d$ is the drift velocity.The current density $J$ is defined as $J = \frac{I}{A} = n e v_d$.According to Ohm's law in microscopic form,the current density $J$ is related to the electric field $E$ by the relation $J = \sigma E$,where $\sigma$ is the electrical conductivity.Equating the two expressions for $J$,we get $n e v_d = \sigma E$.Since $n$,$e$,and $\sigma$ are constants for a given material at a constant temperature,it follows that $v_d \propto E$.

Drift velocity $V_d$ varies with the intensity of electric field $E$ as per the relation:

Similar Questions

When there is an electric current through a conducting wire along its length,then an electric field must exist

The lengths of two wires made of the same material are in the ratio $2:3$ and their radii are in the ratio $1:2$. If the two wires are connected in parallel to a battery,then the ratio of the drift velocities of free electrons in the two wires is

Which of the following is a vector quantity?

Assertion : The electric bulb glows immediately when the switch is on.
Reason : The drift velocity of electrons in a metallic wire is very high.

The electric current passing through a metallic wire produces heat because of

Vedclass Test Series

Exam Paper Generator

Online Exam Module