Each of the two boxes $A$ and $B$ contain $10$ chits numbered $1$ to $10$. If one chit is drawn at random from each of $A$ and $B$,then the probability that the number on the chit drawn from $A$ is smaller than the number on the chit drawn from $B$,is

  • A
    $\frac{9}{10}$
  • B
    $\frac{9}{20}$
  • C
    $\frac{19}{20}$
  • D
    $\frac{17}{20}$

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