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(C) The angular momentum $L$ of a particle in circular motion is given by $L = mvr$,where $m$ is the mass of the earth,$v$ is its orbital velocity,and

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$\sqrt{R}$

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(C) The angular momentum $L$ of a particle in circular motion is given by $L = mvr$,where $m$ is the mass of the earth,$v$ is its orbital velocity,and $r$ is the radius of the orbit $R$.For a planet revolving around the sun,the centripetal force is provided by the gravitational force:$\frac{mv^2}{R} = \frac{GMm}{R^2}$Solving for $v$,we get $v = \sqrt{\frac{GM}{R}}$.Substituting this into the expression for angular momentum:$L = m 	imes \sqrt{\frac{GM}{R}} 	imes R$$L = m \sqrt{GM} 	imes \frac{R}{\sqrt{R}}$$L = m \sqrt{GM} 	imes \sqrt{R}$Since $m$,$G$,and $M$ are constants,we find that $L \propto \sqrt{R}$.

Earth revolves around the sun in a circular orbit of radius $R$. The angular momentum of the revolving earth is directly proportional to

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