Express the following in the form a+ib:i^{-35 | vedclass

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(A) Given expression is $i^{-35}$.We know that $i^{-35} = \frac{1}{i^{35}}$.Since $i^4 = 1$,we can write $i^{35} = i^{32} 	imes i^3 = (i^4)^8 	imes

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$0+i$

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(A) Given expression is $i^{-35}$.We know that $i^{-35} = \frac{1}{i^{35}}$.Since $i^4 = 1$,we can write $i^{35} = i^{32} 	imes i^3 = (i^4)^8 	imes i^3 = 1^8 	imes (-i) = -i$.Therefore,$i^{-35} = \frac{1}{-i}$.Multiplying the numerator and denominator by $i$,we get $\frac{1 	imes i}{-i 	imes i} = \frac{i}{-i^2} = \frac{i}{-(-1)} = \frac{i}{1} = i$.In the form $a+ib$,this is $0+1i$.

Express the following in the form $a+ib$:
$i^{-35}$

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Express the following in the form $a+ib$:$i^{-35}$