Factorise 144 x^{2}-289 y^{2}. | vedclass

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Question

(A) To factorise the expression $144 x^{2}-289 y^{2}$,we use the algebraic identity $a^{2}-b^{2}=(a-b)(a+b)$.First,express the given terms as squares:

Vedclass · Accepted Answer

$(12 x+17 y)(12 x-17 y)$

Vedclass · Answer

(A) To factorise the expression $144 x^{2}-289 y^{2}$,we use the algebraic identity $a^{2}-b^{2}=(a-b)(a+b)$.First,express the given terms as squares:$144 x^{2} = (12 x)^{2}$$289 y^{2} = (17 y)^{2}$Now,substitute these into the identity:$144 x^{2}-289 y^{2} = (12 x)^{2}-(17 y)^{2}$Using the identity $a^{2}-b^{2}=(a-b)(a+b)$,where $a=12 x$ and $b=17 y$,we get:$(12 x-17 y)(12 x+17 y)$.

Factorise $144 x^{2}-289 y^{2}$.

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