The figure shows the variation of the gravita | vedclass

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(D) For $r \ge R$,the gravitational acceleration is given by $a_g = \frac{GM}{r^2}$.Substituting $M = \rho \cdot \frac{4}{3} \pi R^3$,we get $a_g = \f

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$1, 2, 4, 3$

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(D) For $r \ge R$,the gravitational acceleration is given by $a_g = \frac{GM}{r^2}$.Substituting $M = \rho \cdot \frac{4}{3} \pi R^3$,we get $a_g = \frac{G}{r^2} \cdot \rho \cdot \frac{4}{3} \pi R^3 = \frac{4}{3} \pi G \rho \frac{R^3}{r^2}$.At the surface $(r = R)$,$a_g = \frac{4}{3} \pi G \rho R$.Since plots $1$ and $2$ coincide for $r \ge R_2$,they represent the same mass $M_1 = M_2$. Since $R_1  \rho_2$.Similarly,for plots $3$ and $4$,$M_3 = M_4$ and $R_3  \rho_4$.Comparing the values at the surface,the acceleration is higher for $1$ and $2$ than for $3$ and $4$,implying $M_{1,2} > M_{3,4}$.Given the curves,the density $\rho \propto \frac{a_g}{R}$. Analyzing the surface values and radii,the descending order of density is $1, 2, 4, 3$.

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