Find a quadratic polynomial,each with the given numbers as the sum and product of its zeroes respectively: $0, \sqrt{5}$.

(D) Let the quadratic polynomial be $p(x) = ax^2 + bx + c$,and its zeroes be $\alpha$ and $\beta$.
The sum of the zeroes is given by $\alpha + \beta = 0 = \frac{0}{1} = -\frac{b}{a}$.
The product of the zeroes is given by $\alpha \times \beta = \sqrt{5} = \frac{\sqrt{5}}{1} = \frac{c}{a}$.
Comparing the coefficients,if we take $a = 1$,then $b = 0$ and $c = \sqrt{5}$.
Substituting these values into the general form $ax^2 + bx + c$,we get the quadratic polynomial $x^2 + 0x + \sqrt{5}$,which simplifies to $x^2 + \sqrt{5}$.