Find the area under the given curve $y=x^{2}$ bounded by the lines $x=1$,$x=2$ and the $x$-axis.

The area of the region bounded by the curve $y = \cos x$,$x = 0$,and $x = 3\pi$ is . . . . . . sq. units.

The area of the smaller region bounded by the circle $x^2 + y^2 = 4$ and the line $x = 1$ is...

The graphs of $f(x) = x^2$ and $g(x) = cx^3$ (where $c > 0$) intersect at the points $(0, 0)$ and $\left( \frac{1}{c}, \frac{1}{c^2} \right)$. If the area of the region lying between these graphs over the interval $[0, 1/c]$ is equal to $2/3$,then the value of $c$ is:

The area of the region bounded by the line $y=3x$ and the curve $y=x^2$ in square units is

Using integration,find the area of the region bounded by the triangle whose vertices are $(1, 0)$,$(2, 2)$,and $(3, 1)$.