Find the derivative of tan (2 x+3) | vedclass

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(A) Let $f(x) = 	an(2 x+3)$.To find the derivative,we use the chain rule.Let $u = 2 x+3$. Then $f(x) = 	an(u)$.The derivative of $	an(u)$ with resp

Vedclass · Accepted Answer

$2 \sec^{2}(2 x+3)$

Vedclass · Answer

(A) Let $f(x) = 	an(2 x+3)$.To find the derivative,we use the chain rule.Let $u = 2 x+3$. Then $f(x) = 	an(u)$.The derivative of $	an(u)$ with respect to $u$ is $\sec^{2}(u)$.The derivative of $u = 2 x+3$ with respect to $x$ is $\frac{du}{dx} = 2$.By the chain rule,$\frac{df}{dx} = \frac{df}{du} \cdot \frac{du}{dx}$.Substituting the values,we get $\frac{df}{dx} = \sec^{2}(u) \cdot 2$.Replacing $u$ with $2 x+3$,we get $\frac{df}{dx} = 2 \sec^{2}(2 x+3)$.

Find the derivative of $\tan (2 x+3)$

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