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Question

(C) The reaction of $3,3-	ext{dimethyl-1-butene}$ with $HCl$ proceeds via a carbocation intermediate.First,the protonation of the double bond occurs

Vedclass · Accepted Answer

$CH_3-C(Cl)(CH_3)-CH(CH_3)-CH_3$

Vedclass · Answer

(C) The reaction of $3,3-	ext{dimethyl-1-butene}$ with $HCl$ proceeds via a carbocation intermediate.First,the protonation of the double bond occurs to form a secondary carbocation: $CH_3-C(CH_3)_2-CH^+-CH_3$.This secondary carbocation is less stable and undergoes a $1,2-	ext{methyl shift}$ to form a more stable tertiary carbocation: $CH_3-C^+(CH_3)-CH(CH_3)-CH_3$.Finally,the chloride ion $(Cl^-)$ attacks this tertiary carbocation to form $2-	ext{chloro-2,3-dimethylbutane}$ as the major product.

Find the major product of the following reaction: $CH_3-C(CH_3)_2-CH=CH_2 \xrightarrow{HCl} ?$

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