Find the rate of change of the area of a circle with respect to its radius $r$ when $r=5 \text{ cm}$.

  • A
    $5 \pi \text{ cm}^2/\text{cm}$
  • B
    $10 \pi \text{ cm}^2/\text{cm}$
  • C
    $25 \pi \text{ cm}^2/\text{cm}$
  • D
    $20 \pi \text{ cm}^2/\text{cm}$

Explore More

Similar Questions

$A$ sphere increases its volume at the rate of $\pi \text{ cm}^3/\text{s}$. The rate at which its surface area increases when the radius is $1 \text{ cm}$ is

The distance $s$ (in meters) covered by a particle in $t$ seconds is given by $s = ae^t + \frac{b}{e^t}$. Then the acceleration of the particle at time $t$ is:

$A$ spherical balloon is filled with $4500\pi$ cubic meters of helium gas. If a leak in the balloon causes the gas to escape at the rate of $72\pi$ cubic meters per minute,then the rate (in meters per minute) at which the radius of the balloon decreases $49$ minutes after the leakage began is:

The radius of a circle is increasing at the rate of $0.7 \, cm/s$. What is the rate of increase of its circumference?

The volume of a cube increases at a constant rate. Prove that the increase in its surface area varies inversely as the length of the side.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo