Find the time required for a $50 \text{ Hz}$ alternating current to reach its $rms$ value from zero. (in $\text{ ms}$)

In an $A.C.$ circuit,the instantaneous current and $E.M.F.$ are represented as $i = i_0 \sin(\omega t - \frac{\pi}{6})$ and $E = E_0 \sin(\omega t + \frac{\pi}{3})$ respectively. The voltage leads the current by

An alternating voltage is given by: $e = e_1 \sin \omega t + e_2 \cos \omega t$. Then the root mean square $(RMS)$ value of the voltage is given by:

The sinusoidal potential difference $V_1$ shown in the figure is applied across a resistor $R$,producing heat at a rate $W$. What is the rate of heat dissipation when the square wave potential difference $V_2$ as shown in the figure is applied across the same resistor?

The a.c. source of e.m.f. with instantaneous value $e$ is given by $e = 200 \sin(50t) \text{ V}$. The r.m.s. value of current in a circuit of resistance $50 \ \Omega$ is: (in $\text{ A}$)

An $ac$ source is rated at $220V, 50 Hz$. The time taken for voltage to change from its peak value to zero is.....$sec$.