An alternating voltage is given by: e = e_1 s | vedclass

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(D) The given voltage is $e = e_1 \sin \omega t + e_2 \cos \omega t$.We can rewrite this as $e = E_0 \sin(\omega t + \phi)$,where $E_0 = \sqrt{e_1^2 +

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$\sqrt{\frac{e_1^2 + e_2^2}{2}}$

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(D) The given voltage is $e = e_1 \sin \omega t + e_2 \cos \omega t$.We can rewrite this as $e = E_0 \sin(\omega t + \phi)$,where $E_0 = \sqrt{e_1^2 + e_2^2}$ is the peak voltage.The root mean square $(RMS)$ value of an alternating voltage $e = E_0 \sin(\omega t + \phi)$ is given by $V_{rms} = \frac{E_0}{\sqrt{2}}$.Substituting the value of $E_0$,we get $V_{rms} = \frac{\sqrt{e_1^2 + e_2^2}}{\sqrt{2}} = \sqrt{\frac{e_1^2 + e_2^2}{2}}$.

An alternating voltage is given by: $e = e_1 \sin \omega t + e_2 \cos \omega t$. Then the root mean square $(RMS)$ value of the voltage is given by:

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