Find the zeros of the quadratic polynomial $p(x) = 10x^2 - 14x - 12$ and also find the sum and the product of the zeros of the polynomial.

(N/A) Given polynomial is $p(x) = 10x^2 - 14x - 12$.
To find the zeros,we factorize the polynomial:
$10x^2 - 14x - 12 = 10x^2 - 20x + 6x - 12$
$= 10x(x - 2) + 6(x - 2)$
$= (10x + 6)(x - 2)$
Setting $p(x) = 0$,we get $(10x + 6)(x - 2) = 0$.
This gives $x = -6/10 = -3/5$ or $x = 2$.
Thus,the zeros are $-3/5$ and $2$.
Using the relationship between zeros and coefficients for $ax^2 + bx + c$:
Sum of zeros $= -b/a = -(-14)/10 = 14/10 = 7/5$.
Product of zeros $= c/a = -12/10 = -6/5$.