Five current-carrying conductors meet at poin | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Kirchhoff's first law (junction rule), the algebraic sum of currents meeting at a junction is zero. Let the current $I$ in conductor

Vedclass · Accepted Answer

$1 \,A$ from $P$ to $Q$

Vedclass · Answer

(B) According to Kirchhoff's first law (junction rule), the algebraic sum of currents meeting at a junction is zero. Let the current $I$ in conductor $PQ$ be directed away from point $P$.Sum of incoming currents = Sum of outgoing currents$5 \,A + 4 \,A = 5 \,A + 3 \,A + I$$9 \,A = 8 \,A + I$$I = 9 \,A - 8 \,A = 1 \,A$Since the result is positive, the assumed direction (away from $P$) is correct. Therefore, $1 \,A$ current flows from $P$ to $Q$.

Five current-carrying conductors meet at point $P$. What is the magnitude and direction of the current in conductor $PQ$?

Similar Questions

The equivalent resistance between points $A$ and $B$ is ............ $\Omega$.

Determine the current in each branch of the network shown in Figure.

What is the equivalent resistance between $X$ and $Y$ in the given circuit?

The figure shows currents in a part of an electric circuit. Then the current $I$ is: (in $A$)

Find the potential difference $(V_A - V_B)$ for the given circuit.

Vedclass Test Series

Exam Paper Generator

Online Exam Module