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(A) Step $1$: Calculate the mean value of the observations.Mean value $a_{mean} = \frac{3.29 + 3.28 + 3.29 + 3.31 + 3.28 + 3.27 + 3.29 + 3.30}{8} = \f

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$0.02 \, cm, 0.01 \, cm$

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(A) Step $1$: Calculate the mean value of the observations.Mean value $a_{mean} = \frac{3.29 + 3.28 + 3.29 + 3.31 + 3.28 + 3.27 + 3.29 + 3.30}{8} = \frac{26.31}{8} = 3.28875 \, cm \approx 3.29 \, cm$.Step $2$: Calculate the absolute error for the fourth observation $(a_4 = 3.31 \, cm)$.Absolute error $\Delta a_4 = a_4 - a_{mean} = 3.31 - 3.29 = 0.02 \, cm$.Step $3$: Calculate the absolute error for the eighth observation $(a_8 = 3.30 \, cm)$.Absolute error $\Delta a_8 = a_8 - a_{mean} = 3.30 - 3.29 = 0.01 \, cm$.Thus,the absolute errors are $0.02 \, cm$ and $0.01 \, cm$.

Following observations were taken with a vernier callipers while measuring the length of a cylinder:
$3.29 \, cm, 3.28 \, cm, 3.29 \, cm, 3.31 \, cm, 3.28 \, cm, 3.27 \, cm, 3.29 \, cm, 3.30 \, cm$
Find the absolute error in the fourth and eighth observations.

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Following observations were taken with a vernier callipers while measuring the length of a cylinder:$3.29 \, cm, 3.28 \, cm, 3.29 \, cm, 3.31 \, cm, 3.28 \, cm, 3.27 \, cm, 3.29 \, cm, 3.30 \, cm$Find the absolute error in the fourth and eighth observations.