For n in N,what is the value of 1+4+7+cdots+( | vedclass

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(C) The given series is $1+4+7+\cdots+(3n-2)$.This is an arithmetic progression where the first term $a = 1$ and the common difference $d = 4-1 = 3$.T

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$\frac{n(3n-1)}{2}$

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(C) The given series is $1+4+7+\cdots+(3n-2)$.This is an arithmetic progression where the first term $a = 1$ and the common difference $d = 4-1 = 3$.The number of terms is $n$.The sum of the first $n$ terms of an arithmetic progression is given by the formula $S_n = \frac{n}{2}[2a + (n-1)d]$.Substituting the values $a=1$ and $d=3$ into the formula:$S_n = \frac{n}{2}[2(1) + (n-1)3]$$S_n = \frac{n}{2}[2 + 3n - 3]$$S_n = \frac{n(3n-1)}{2}$.

For $n \in N$,what is the value of $1+4+7+\cdots+(3n-2)$?

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