If the sum of $n$ terms of an $A$.$P$. is $3n^2 + 5n$ and its $m$th term is $164$, then the value of $m$ is

  • A
    $26$
  • B
    $27$
  • C
    $28$
  • D
    $29$

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The first term of an $A.P.$ is $2$ and the common difference is $4$. The sum of its $40$ terms will be:

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