For a given A.P.,S_{20} = 100 and d = -2. The | vedclass

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(C) The formula for the sum of the first $n$ terms of an $A.P.$ is $S_{n} = \frac{n}{2} [2a + (n - 1)d]$.Given $S_{20} = 100$,$n = 20$,and $d = -2$.Su

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$24$

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(C) The formula for the sum of the first $n$ terms of an $A.P.$ is $S_{n} = \frac{n}{2} [2a + (n - 1)d]$.Given $S_{20} = 100$,$n = 20$,and $d = -2$.Substituting these values into the formula:$100 = \frac{20}{2} [2a + (20 - 1)(-2)]$$100 = 10 [2a + (19)(-2)]$$100 = 10 [2a - 38]$Dividing both sides by $10$:$10 = 2a - 38$$2a = 10 + 38$$2a = 48$$a = 24$.

For a given $A.P.$,$S_{20} = 100$ and $d = -2$. Then,$a = \ldots$

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