For a satellite moving in an orbit around the earth,the ratio of kinetic energy to potential energy is

$A$ particle of mass $m$ moves in a horizontal circle of radius $r$ under the influence of a centripetal force given by $F = -k/r^2$,where $k$ is a constant. Calculate the total energy of the particle.

The additional kinetic energy to be provided to a satellite of mass $m$ revolving around a planet of mass $M$ to transfer it from a circular orbit of radius $R_1$ to another of radius $R_2$ $(R_2 > R_1)$ is:

Write an equation of total energy of a satellite. Why is the total energy of a satellite negative?

For a satellite orbiting around the earth in a circular orbit,the ratio of potential energy to kinetic energy at the same height is

$A$ satellite of mass $m$ is orbiting the Earth (of radius $R$) at a height equal to the radius of the Earth. The total energy of the satellite in terms of $g$ (acceleration due to gravity on Earth's surface) is