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Question

(B) The $pH$ of an acidic buffer is given by the Henderson-Hasselbalch equation: $pH = pK_a + \log \frac{[Salt]}{[Acid]}$.Given $pH = 5$ and $K_a = 10

Vedclass · Accepted Answer

$1 : 1$

Vedclass · Answer

(B) The $pH$ of an acidic buffer is given by the Henderson-Hasselbalch equation: $pH = pK_a + \log \frac{[Salt]}{[Acid]}$.Given $pH = 5$ and $K_a = 10^{-5}$.First,calculate $pK_a$: $pK_a = -\log(K_a) = -\log(10^{-5}) = 5$.Substitute the values into the equation: $5 = 5 + \log \frac{[Salt]}{[Acid]}$.$0 = \log \frac{[Salt]}{[Acid]}$.Taking the antilog on both sides: $\frac{[Salt]}{[Acid]} = 10^0 = 1$.Therefore,the ratio of the concentration of salt to acid is $1 : 1$.

For preparing a buffer solution of $pH = 5$ by mixing sodium acetate and acetic acid,the ratio of the concentration of salt and acid should be $(K_a = 10^{-5})$:-

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