For the forward biased diode characteristics | vedclass

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Question

(A) The dynamic resistance $R_{d}$ is defined as the reciprocal of the slope of the $I-V$ characteristic curve.$R_{d} = \frac{\Delta V}{\Delta I} = \f

Vedclass · Accepted Answer

$25$

Vedclass · Answer

(A) The dynamic resistance $R_{d}$ is defined as the reciprocal of the slope of the $I-V$ characteristic curve.$R_{d} = \frac{\Delta V}{\Delta I} = \frac{1}{	ext{slope}} = \frac{1}{\frac{\Delta I}{\Delta V}}$From the given graph,we select two points on the linear portion of the curve around $I_{D} = 3 \, 	ext{mA}$.At $I_{D1} = 1 \, 	ext{mA}$,$V_{D1} = 0.65 \, 	ext{V}$.At $I_{D2} = 5 \, 	ext{mA}$,$V_{D2} = 0.75 \, 	ext{V}$.Calculating the change in current and voltage:$\Delta I = (5 - 1) \, 	ext{mA} = 4 	imes 10^{-3} \, 	ext{A}$$\Delta V = 0.75 \, 	ext{V} - 0.65 \, 	ext{V} = 0.10 \, 	ext{V}$Therefore,$R_{d} = \frac{\Delta V}{\Delta I} = \frac{0.10}{4 	imes 10^{-3}} = \frac{100}{4} = 25 \, \Omega$.

For the forward biased diode characteristics shown in the figure,the dynamic resistance at $I_{D} = 3 \, \text{mA}$ will be $..... \, \Omega$.

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