For the reaction shown,the correct order of t | vedclass

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(B) The conversion of aniline to $o$-bromoaniline requires protecting the highly activating $-NH_2$ group to prevent poly-bromination and to control t

Vedclass · Accepted Answer

$H_2SO_4, Ac_2O, Br_2, H_2O (\Delta), NaOH$

Vedclass · Answer

(B) The conversion of aniline to $o$-bromoaniline requires protecting the highly activating $-NH_2$ group to prevent poly-bromination and to control the regioselectivity.$1$. First,aniline is treated with acetic anhydride $(Ac_2O)$ to form acetanilide,which reduces the activating power of the nitrogen atom.$2$. Then,bromination is carried out using $Br_2$ in acetic acid or water. The acetamido group is ortho/para directing,and the bulky group favors the para product,but under specific conditions,ortho-substitution can be controlled or separated.$3$. Finally,the acetyl group is removed by hydrolysis using $H_2O (\Delta)$ or $NaOH$ to regenerate the $-NH_2$ group.$4$. The provided reaction sequence in the image shows the use of $H_2SO_4$ to protect the amino group via sulfonation,followed by acetylation,bromination,and subsequent hydrolysis to remove the sulfonic acid and acetyl groups. Among the given options,option $B$ represents the most complete sequence for this specific transformation.

For the reaction shown,the correct order of the set of reagents for the conversion is:

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