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(C) To determine the basic strength,we analyze the availability of the lone pair on the nitrogen atom:$1$. $(Q)$ is $N$-methylpiperidine,a tertiary al

Vedclass · Accepted Answer

$Q > P > S > R$

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(C) To determine the basic strength,we analyze the availability of the lone pair on the nitrogen atom:$1$. $(Q)$ is $N$-methylpiperidine,a tertiary aliphatic amine where the nitrogen is $sp^3$ hybridized and the lone pair is localized,making it the most basic.$2$. $(P)$ is pyridine,where the nitrogen is $sp^2$ hybridized. The lone pair is in an $sp^2$ orbital,which is more electronegative than an $sp^3$ orbital,making it less basic than $(Q)$.$3$. $(S)$ is aniline,where the lone pair on the nitrogen is involved in resonance with the benzene ring,significantly reducing its availability for protonation.$4$. $(R)$ is $\delta$-valerolactam,an amide. The lone pair on the nitrogen is delocalized into the carbonyl group $(C=O)$ via resonance,making it the least basic among the given compounds.Therefore,the order of basic strength is $(Q) > (P) > (S) > (R)$.

Write the order of basic strength for the following compounds:

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