The reaction of RCONH_2 with bromine and KOH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given reaction is the Hoffmann-Bromamide degradation reaction. In this reaction,the amide $(RCONH_2)$ reacts with $Br_2$ and $KOH$ to form an

Vedclass · Accepted Answer

$RN=C=O$

Vedclass · Answer

(C) The given reaction is the Hoffmann-Bromamide degradation reaction. In this reaction,the amide $(RCONH_2)$ reacts with $Br_2$ and $KOH$ to form an $N$-bromamide intermediate $(RCONHBr)$,which then undergoes rearrangement to form an isocyanate intermediate $(RN=C=O)$. Finally,the isocyanate is hydrolyzed to form the primary amine $(RNH_2)$. Both $RCONHBr$ and $RN=C=O$ are intermediates,but $RN=C=O$ (alkyl isocyanate) is the key intermediate formed during the rearrangement step.

The reaction of $RCONH_2$ with bromine and $KOH$ gives $RNH_2$ as the end product. Which one of the following is the intermediate product formed in this reaction?

Similar Questions

Arrange the given amines in decreasing order of their basicity.

Arrange the following compounds in their correct order of $pK_b$ values.

What is the product formed when an aliphatic primary amine reacts with $HNO_2$?

In the sequence of the following reactions,$X$ and $Y$ are respectively: $CH_3OH$ $\xrightarrow{HI} CH_3I$ $\xrightarrow{KCN} CH_3CN$ $\xrightarrow{\text{reduction}} X$ $\xrightarrow{HNO_2} Y$

Identify the product obtained when benzamide is treated with bromine and aqueous sodium hydroxide.

Vedclass Test Series

Exam Paper Generator

Online Exam Module