Four years ago,the sum of the ages of four pe | vedclass

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(A) Let the current ages of the four persons be $a, b, c,$ and $d$.Four years ago,the sum of their ages was $(a-4) + (b-4) + (c-4) + (d-4) = 40$.This

Vedclass · Accepted Answer

$64$

Vedclass · Answer

(A) Let the current ages of the four persons be $a, b, c,$ and $d$.Four years ago,the sum of their ages was $(a-4) + (b-4) + (c-4) + (d-4) = 40$.This simplifies to $a + b + c + d - 16 = 40$,which means $a + b + c + d = 56$.This is the sum of their current ages.After two years,the sum of their ages will be $(a+2) + (b+2) + (c+2) + (d+2)$.This equals $(a + b + c + d) + 8$.Substituting the current sum,we get $56 + 8 = 64$ years.

Four years ago,the sum of the ages of four persons was $40$ years. After two years,the sum of the ages of the same four persons will be ............ years.

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