From $6.55 \ g$ of aniline,the maximum amount of acetanilide that can be prepared will be _ $\times 10^{-1} \ g$.

Accomplish the following conversions:
$(i)$ Nitrobenzene to benzoic acid
$(ii)$ Benzene to $m-$bromophenol
$(iii)$ Benzoic acid to aniline
$(iv)$ Aniline to $2,4,6-$tribromofluorobenzene
$(v)$ Benzyl chloride to $2-$phenylethanamine
$(vi)$ Chlorobenzene to $p-$chloroaniline
$(vii)$ Aniline to $p-$bromoaniline
$(viii)$ Benzamide to toluene
$(ix)$ Aniline to benzyl alcohol.

Which among the following represents reagent $A$ in the given reaction?
$C_6H_5N_2^+Cl^- + A \xrightarrow{NaOH} \text{Product (Orange-red dye)}$

Identify $A$ and $B$ in the following reaction sequence:
Aniline $\xrightarrow[KCN]{NaNO_2/HCl} (A)$ $\xrightarrow{SnCl_2/HCl/H_3O^+} (B)$

Give a plausible explanation for each of the following:
$(i)$ Why are amines less acidic than alcohols of comparable molecular masses?
$(ii)$ Why do primary amines have higher boiling points than tertiary amines?
$(iii)$ Why are aliphatic amines stronger bases than aromatic amines?

The final product $A$, formed in the following multistep reaction sequence is: