From the following,the quantity (constructed | vedclass

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(A) The classical electron radius $r_e$ is defined by equating the electrostatic potential energy of an electron to its rest mass energy.$mc^2 = \frac

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$\frac{e^2}{4\pi \varepsilon_0 mc^2}$

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(A) The classical electron radius $r_e$ is defined by equating the electrostatic potential energy of an electron to its rest mass energy.$mc^2 = \frac{1}{4\pi \varepsilon_0} \frac{e^2}{r_e}$Rearranging for $r_e$:$r_e = \frac{e^2}{4\pi \varepsilon_0 mc^2}$Substituting the values of the constants ($e \approx 1.6 	imes 10^{-19} \ C$,$\varepsilon_0 \approx 8.85 	imes 10^{-12} \ F/m$,$m \approx 9.1 	imes 10^{-31} \ kg$,$c \approx 3 	imes 10^8 \ m/s$),we get $r_e \approx 2.8 	imes 10^{-15} \ m$,which is the order of magnitude for the size of an atom/nucleus related constant.

From the following,the quantity (constructed from the basic constants of nature) that has the dimensions of length,as well as the correct order of magnitude for a typical atomic size,is:

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