Give reason for the higher boiling point of ethanol in comparison to methoxymethane.
(N/A) Ethanol $(C_2H_5OH)$ undergoes intermolecular hydrogen bonding due to the presence of the polar $-OH$ group,which leads to the association of molecules.
Extra energy is required to break these hydrogen bonds during the phase transition from liquid to gas.
On the other hand,methoxymethane $(CH_3OCH_3)$ is an ether and does not possess an $-OH$ group,so it does not undergo intermolecular hydrogen bonding.
Hence,the boiling point of ethanol is significantly higher than that of methoxymethane.
Extra energy is required to break these hydrogen bonds during the phase transition from liquid to gas.
On the other hand,methoxymethane $(CH_3OCH_3)$ is an ether and does not possess an $-OH$ group,so it does not undergo intermolecular hydrogen bonding.
Hence,the boiling point of ethanol is significantly higher than that of methoxymethane.
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