Given below are two statements:
Statement $I$: One mole of propyne reacts with excess of sodium to liberate half a mole of $H_2$ gas.
Statement $II$: Four $g$ of propyne reacts with $NaNH_2$ to liberate $NH_3$ gas which occupies $224 \ mL$ at $STP$.
In the light of the above statements,choose the most appropriate answer from the options given below:

  • A
    Statement $I$ is correct but Statement $II$ is incorrect.
  • B
    Both Statement $I$ and Statement $II$ are incorrect.
  • C
    Statement $I$ is incorrect but Statement $II$ is correct.
  • D
    Both Statement $I$ and Statement $II$ are correct.

Explore More

Similar Questions

Compound $(X)$ [styrene] is subjected to the following sequence of reactions: $(i)$ $Br_2/CHCl_3$, $(ii)$ $NaNH_2$ (excess), $(iii)$ $CH_3I$, $(iv)$ $H_2, Na/NH_3(l)$, giving Major Product $(Y)$. The molar mass of the major product $(Y)$ formed is . . . . . . $\text{g mol}^{-1}$. (Given molar mass in $\text{g mol}^{-1}$: $C:12, H:1$)

The reagent needed for converting $Ph-C \equiv C-Ph$ to trans-stilbene is:

The final product of the following reaction is .......
$CaO + 3C$ $\xrightarrow{\text{Heat}} A$ $\xrightarrow{H_2O} B$ $\xrightarrow{H_2SO_4, Hg^{2+}} C$

Which reacts with ammoniacal $AgNO_3$?

$CH \equiv CH + CO + H_2O \xrightarrow{Ni(CO)_4} \text{Product}$. For this reaction,which statement is false?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo