Given that Delta T_f is the depression in fre | vedclass

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(D) The depression in freezing point $(\Delta T_f)$ is given by the formula: $\Delta T_f = K_f 	imes m$,where $K_f$ is the molal freezing point depre

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The cryoscopic constant $(K_f)$

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(D) The depression in freezing point $(\Delta T_f)$ is given by the formula: $\Delta T_f = K_f 	imes m$,where $K_f$ is the molal freezing point depression constant (cryoscopic constant) and $m$ is the molality of the solution.Rearranging the equation,we get: $\frac{\Delta T_f}{m} = K_f$.Since $K_f$ is a constant characteristic of the solvent,the limit as $m 	o 0$ of the ratio $\frac{\Delta T_f}{m}$ is simply $K_f$.Therefore,the quantity $\lim_{m 	o 0} \left( \frac{\Delta T_f}{m} ight)$ is equal to $K_f$.

Given that $\Delta T_f$ is the depression in freezing point of the solvent in a solution of a non-volatile solute of molality $m$,the quantity $\lim_{m \to 0} \left( \frac{\Delta T_f}{m} \right)$ is equal to:

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