Hex$-4-$en$-2-$ol on treatment with $PCC$ gives $'A'.$ $'A'$ on reaction with sodium hypoiodite gives $'B',$ which on further heating with soda lime gives $'C'.$ The compound $'C'$ is $....... .$

Compound $A$ $(C_3H_6O)$ undergoes the following reactions to form $B$ and $C$. Identify $A, B$ and $C$.

$(A)$ $\xrightarrow{NH_2OH} (B)$ $\xrightarrow{H_2SO_4} (C)$ $\xrightarrow{H_3O^{\oplus}} (D) + (E)$ $\xrightarrow{CHCl_3, KOH} CH_3-NC$ (carbylamine test). $(D)$ $\xrightarrow{SOCl_2} (F)$ $\xrightarrow{(i) PhMgBr \text{ (excess) } (ii) H^{\oplus}} (G)$ $\xrightarrow[\Delta]{H^{\oplus}} (H)$ $\xrightarrow{CH_2I_2, Zn/Cu} \text{1,1-diphenylcyclopropane}$. The molecular weight of compound $(A)$ is:

$A$ strong base can abstract an $\alpha$-hydrogen from

When an oxime is treated with trifluoroperoxyacetic acid,it yields:

The product $P$ is: