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(D) The given compound contains two ester groups. One is attached directly to the cyclohexane ring (sterically hindered),and the other is attached via

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(D) The given compound contains two ester groups. One is attached directly to the cyclohexane ring (sterically hindered),and the other is attached via a $-CH_2-$ group (less sterically hindered).When $1 \ equivalent$ of $PhMgBr$ is added,it acts as a nucleophile.Due to steric hindrance,the nucleophilic attack by $Ph^-$ occurs at the less sterically hindered carbonyl carbon of the $-CH_2COOCH_3$ group.This results in the formation of a ketone,where the $-OCH_3$ group is replaced by the $-Ph$ group.The final product $P$ is the one where the phenyl group is attached to the carbonyl carbon of the side chain ester.

The product $P$ is:

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