How does ammonia react with a solution of $Cu^{2+}$?
- AIt forms a white precipitate of $Cu(OH)_2$.
- BIt forms a deep blue complex $[Cu(NH_3)_4]^{2+}$.
- CIt reduces $Cu^{2+}$ to $Cu^+$.
- DIt forms a brown precipitate of $Cu_2O$.
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Similar Questions
Which among the following cations will form the lowest stability complex if the ligand remains the same?
The $\pi-$acid ligand which uses its $d-$orbital during synergic bonding in its complex compound is:
$CuSO_4$ reacts with $KCN$ solution and forms:
Difficult
View SolutionWhich of the following is the most stable complex?
Difficult
View SolutionGive the correct order of electrical conductivity of aqueous solution of the following complexes:
$A$. $[Pt(NH_3)_6]Cl_4$
$B$. $[Cr(NH_3)_6]Cl_3$
$C$. $[Co(NH_3)_4Cl_2]Cl$
$D$. $K_2[PtCl_6]$
$A$. $[Pt(NH_3)_6]Cl_4$
$B$. $[Cr(NH_3)_6]Cl_3$
$C$. $[Co(NH_3)_4Cl_2]Cl$
$D$. $K_2[PtCl_6]$
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