How much work does a pulling force of 40, N d | vedclass

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(A) The work done $W$ by a constant force $F$ is given by the formula $W = F \cdot S \cdot \cos 	heta$,where $S$ is the displacement and $	heta$ is

Vedclass · Accepted Answer

$160$

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(A) The work done $W$ by a constant force $F$ is given by the formula $W = F \cdot S \cdot \cos 	heta$,where $S$ is the displacement and $	heta$ is the angle between the force and the displacement vector.Given:Force $F = 40\, N$Displacement $S = 8\, m$Angle $	heta = 60^{\circ}$Substituting these values into the formula:$W = 40 	imes 8 	imes \cos 60^{\circ}$Since $\cos 60^{\circ} = 0.5$ or $\frac{1}{2}$,we have:$W = 40 	imes 8 	imes 0.5$$W = 320 	imes 0.5 = 160\, J$Therefore,the work done is $160\, J$.

How much work does a pulling force of $40\, N$ do on a $20\, kg$ box in pulling it $8\, m$ across a smooth floor at a constant speed? The pulling force is directed at $60^{\circ}$ above the horizontal. (Answer in $J$)

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