If $A = 100101$ and $B = 110110$ are applied to $X-NOR$ gate,then the output will be

The circuit given below is that of:

The circuit diagram shows a combination of logic gates. When inputs $P$ and $Q$ change to state $0$ with inputs $R$ and $S$ still at state $1$,the states of outputs $X$,$Y$ and $Z$ change to:

To get an output $Y = 1$ in the given circuit,which of the following inputs will be correct?

$A$ logic circuit provides the output $Y$ as per the following truth table:

$A$	$B$	$Y$
$0$	$0$	$1$
$0$	$1$	$0$
$1$	$0$	$1$
$1$	$1$	$0$

The expression for the output $Y$ is:

In the circuit shown, inputs $A$ and $B$ are in states $1$ and $0$ respectively. What is the only possible stable state of the outputs $X$ and $Y$?