If $(a+\sqrt{2} b \cos x)(a-\sqrt{2} b \cos y)=a^{2}-b^{2}$ where $a>b>0,$ then $\frac{dx}{dy}$ at $\left(\frac{\pi}{4}, \frac{\pi}{4}\right)$ is

  • A
    $\frac{a-b}{a+b}$
  • B
    $\frac{a+b}{a-b}$
  • C
    $\frac{2a+b}{2a-b}$
  • D
    $\frac{a-2b}{a+2b}$

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