If frac{a}{3} = frac{b}{8},then (a + 3) : (b | vedclass

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(A) Given that $\frac{a}{3} = \frac{b}{8}$.Let $\frac{a}{3} = \frac{b}{8} = k$,where $k$ is a constant.Then $a = 3k$ and $b = 8k$.We need to find the

Vedclass · Accepted Answer

$3:8$

Vedclass · Answer

(A) Given that $\frac{a}{3} = \frac{b}{8}$.Let $\frac{a}{3} = \frac{b}{8} = k$,where $k$ is a constant.Then $a = 3k$ and $b = 8k$.We need to find the ratio $(a + 3) : (b + 8)$.Substituting the values of $a$ and $b$ in terms of $k$:$(a + 3) : (b + 8) = (3k + 3) : (8k + 8)$.Factor out the common terms:$(3(k + 1)) : (8(k + 1))$.Since $k + 1 
eq 0$,we can cancel $(k + 1)$ from both sides:Ratio $= 3 : 8$.

If $\frac{a}{3} = \frac{b}{8}$,then $(a + 3) : (b + 8)$ is equal to

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