If sqrt{1+frac{55}{729}}=1+frac{x}{27}, then | vedclass

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(A) Given the equation: $\sqrt{1+\frac{55}{729}}=1+\frac{x}{27}$First,simplify the expression inside the square root: $1+\frac{55}{729} = \frac{729+55

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$1$

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(A) Given the equation: $\sqrt{1+\frac{55}{729}}=1+\frac{x}{27}$First,simplify the expression inside the square root: $1+\frac{55}{729} = \frac{729+55}{729} = \frac{784}{729}$Now,take the square root of the fraction: $\sqrt{\frac{784}{729}} = \frac{\sqrt{784}}{\sqrt{729}} = \frac{28}{27}$Substitute this back into the equation: $\frac{28}{27} = 1+\frac{x}{27}$Subtract $1$ from both sides: $\frac{28}{27} - 1 = \frac{x}{27}$$\frac{28-27}{27} = \frac{x}{27}$$\frac{1}{27} = \frac{x}{27}$Therefore,$x = 1$.

If $\sqrt{1+\frac{55}{729}}=1+\frac{x}{27},$ then the value of $x$ is

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