If p and q are the roots of the equation {x^2 | vedclass

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(B) The given quadratic equation is ${x^2} - (p + 1)x + pq = 0$.Since $p$ and $q$ are the roots of this equation,we can use the relationship between r

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$1$

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(B) The given quadratic equation is ${x^2} - (p + 1)x + pq = 0$.Since $p$ and $q$ are the roots of this equation,we can use the relationship between roots and coefficients.According to Vieta's formulas,the sum of the roots is equal to the negative of the coefficient of $x$ divided by the coefficient of ${x^2}$.Therefore,$p + q = -(-(p + 1)) / 1$.This simplifies to $p + q = p + 1$.Subtracting $p$ from both sides,we get $q = 1$.

If $p$ and $q$ are the roots of the equation ${x^2} + pq = (p + 1)x$,then $q=$

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