If A = {x in R : |x|

Question

(C) Given $A = \{x \in R : |x| < 2\}$.This implies $-2 < x < 2$,so $A = (-2, 2)$.Given $B = \{x \in R : |x - 2| \geq 3\}$.This implies $x - 2 \geq 3$

Vedclass · Accepted Answer

$B - A = R - (-2, 5)$

Vedclass · Answer

(C) Given $A = \{x \in R : |x| This implies $-2 Given $B = \{x \in R : |x - 2| \geq 3\}$.This implies $x - 2 \geq 3$ or $x - 2 \leq -3$.So,$x \geq 5$ or $x \leq -1$.Thus,$B = (-\infty, -1] \cup [5, \infty)$.Now,$B - A$ represents the set of elements in $B$ that are not in $A$.$B - A = ((-\infty, -1] \cup [5, \infty)) - (-2, 2)$.Since the interval $(-2, 2)$ overlaps with $(-\infty, -1]$ only on the interval $(-2, -1]$,we remove this part from $B$.$B - A = (-\infty, -2] \cup [5, \infty)$.This can be written as $R - (-2, 5)$.Therefore,the correct option is $C$.

If $A = \{x \in R : |x| < 2\}$ and $B = \{x \in R : |x - 2| \geq 3\}$,then:

Similar Questions

Which of the following pairs of sets are not equivalent?

If $A = \{2, 3, 5\}$ and $B = \{2, 5, 6\}$,then $(A - B) \times (A \cap B)$ is:

If $A$ and $B$ are two sets,then $A \times B = B \times A$ if and only if

If $A = \{1, 2, 3, 4, 5\}, B = \{2, 4, 6\}, C = \{3, 4, 6\},$ then $(A \cup B) \cap C$ is

If $n$ is an integer,the domain of the function $\sqrt{\sin 2x}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module