If sin theta + text{cosec} theta = 2,the valu | vedclass

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(D) Given,$\sin 	heta + 	ext{cosec} 	heta = 2$.Since $	ext{cosec} 	heta = \frac{1}{\sin 	heta}$,the equation becomes $\sin 	heta + \frac{1}{\si

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$2$

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(D) Given,$\sin 	heta + 	ext{cosec} 	heta = 2$.Since $	ext{cosec} 	heta = \frac{1}{\sin 	heta}$,the equation becomes $\sin 	heta + \frac{1}{\sin 	heta} = 2$.Multiplying by $\sin 	heta$,we get $\sin^2 	heta + 1 = 2 \sin 	heta$.Rearranging gives $\sin^2 	heta - 2 \sin 	heta + 1 = 0$,which is $(\sin 	heta - 1)^2 = 0$.Therefore,$\sin 	heta = 1$.Substituting this value into the expression: $\sin^{10} 	heta + 	ext{cosec}^{10} 	heta = (1)^{10} + \left(\frac{1}{1}ight)^{10} = 1 + 1 = 2$.

If $\sin \theta + \text{cosec} \theta = 2$,the value of $\sin^{10} \theta + \text{cosec}^{10} \theta$ is

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