If frac{log x}{2} = frac{log y}{3} = frac{log | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Let $\frac{\log x}{2} = \frac{\log y}{3} = \frac{\log z}{5} = k$.Then,$\log x = 2k$,$\log y = 3k$,and $\log z = 5k$.We need to find $yz$ in terms

Vedclass · Accepted Answer

$x^4$

Vedclass · Answer

(D) Let $\frac{\log x}{2} = \frac{\log y}{3} = \frac{\log z}{5} = k$.Then,$\log x = 2k$,$\log y = 3k$,and $\log z = 5k$.We need to find $yz$ in terms of $x$. Consider $\log(yz) = \log y + \log z$.Substituting the values,$\log(yz) = 3k + 5k = 8k$.Since $\log x = 2k$,we can write $8k = 4(2k) = 4 \log x = \log(x^4)$.Therefore,$\log(yz) = \log(x^4)$,which implies $yz = x^4$.

If $\frac{\log x}{2} = \frac{\log y}{3} = \frac{\log z}{5}$,then $yz$ in terms of $x$ is

Similar Questions

If $\log 2 = 0.30103$ and $\log 3 = 0.4771$,then the number of digits in $(648)^{5}$ is

If $0 < a < 1$,$0 < x < 1$,and $x < a$,then $\log_{a} x$ is:

$\log _{5}\left(1+\frac{1}{5}\right)+\log _{5}\left(1+\frac{1}{6}\right)+\log _{5}\left(1+\frac{1}{7}\right)+\cdots+\log _{5} \left(1+\frac{1}{624}\right)$

$\frac{\log 49 \sqrt{7} + \log 25 \sqrt{5} - \log 4 \sqrt{2}}{\log 17.5} = $

If $x = \log_{2a} a$,$y = \log_{3a} 2a$,and $z = \log_{4a} 3a$,find the value of $yz(2-x)$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module