If sin A + sin^2 A = 1,then the value of the | vedclass

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(A) Given,$\sin A + \sin^2 A = 1$.From this,we can write $\sin A = 1 - \sin^2 A$.Using the identity $\sin^2 A + \cos^2 A = 1$,we know that $1 - \sin^2

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$1$

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(A) Given,$\sin A + \sin^2 A = 1$.From this,we can write $\sin A = 1 - \sin^2 A$.Using the identity $\sin^2 A + \cos^2 A = 1$,we know that $1 - \sin^2 A = \cos^2 A$.Therefore,$\sin A = \cos^2 A$.Squaring both sides,we get $\sin^2 A = (\cos^2 A)^2 = \cos^4 A$.Now,substitute $\sin^2 A = 1 - \cos^2 A$ into the equation:$1 - \cos^2 A = \cos^4 A$.Rearranging the terms,we get $\cos^2 A + \cos^4 A = 1$.

If $\sin A + \sin^2 A = 1$,then the value of the expression $(\cos^2 A + \cos^4 A)$ is

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