If sin theta + sin^2 theta = 1,then cos^2 the | vedclass

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(A) Given that $\sin 	heta + \sin^2 	heta = 1$.We can rewrite this as $\sin 	heta = 1 - \sin^2 	heta$.Using the trigonometric identity $\sin^2 	h

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(A) Given that $\sin 	heta + \sin^2 	heta = 1$.We can rewrite this as $\sin 	heta = 1 - \sin^2 	heta$.Using the trigonometric identity $\sin^2 	heta + \cos^2 	heta = 1$,we know that $1 - \sin^2 	heta = \cos^2 	heta$.Therefore,$\sin 	heta = \cos^2 	heta$.Now,we need to find the value of $\cos^2 	heta + \cos^4 	heta$.Substitute $\cos^2 	heta = \sin 	heta$ into the expression:$\cos^2 	heta + \cos^4 	heta = \sin 	heta + (\cos^2 	heta)^2$.Since $\cos^2 	heta = \sin 	heta$,then $(\cos^2 	heta)^2 = \sin^2 	heta$.So,the expression becomes $\sin 	heta + \sin^2 	heta$.Given that $\sin 	heta + \sin^2 	heta = 1$,the final value is $1$.

If $\sin \theta + \sin^2 \theta = 1$,then $\cos^2 \theta + \cos^4 \theta = \dots$

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