If x+y=-4, then what is the value of x^{3}+y^ | vedclass

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(A) Given the equation $x+y = -4$.Cubing both sides,we get $(x+y)^3 = (-4)^3$.Using the identity $(x+y)^3 = x^3 + y^3 + 3xy(x+y)$,we have $x^3 + y^3 +

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(A) Given the equation $x+y = -4$.Cubing both sides,we get $(x+y)^3 = (-4)^3$.Using the identity $(x+y)^3 = x^3 + y^3 + 3xy(x+y)$,we have $x^3 + y^3 + 3xy(x+y) = -64$.Substitute the value of $(x+y) = -4$ into the equation:$x^3 + y^3 + 3xy(-4) = -64$.$x^3 + y^3 - 12xy = -64$.Adding $64$ to both sides,we get $x^3 + y^3 - 12xy + 64 = -64 + 64$.Therefore,$x^3 + y^3 - 12xy + 64 = 0$.

If $x+y=-4,$ then what is the value of $x^{3}+y^{3}-12xy+64?$

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