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(C) For a cubic polynomial of the form $p(x) = ax^{3} + bx^{2} + cx + d$,the product of the zeros $\alpha \beta \gamma$ is given by the formula $\alph

Vedclass · Accepted Answer

$-8$

Vedclass · Answer

(C) For a cubic polynomial of the form $p(x) = ax^{3} + bx^{2} + cx + d$,the product of the zeros $\alpha \beta \gamma$ is given by the formula $\alpha \beta \gamma = -\frac{d}{a}$.Comparing the given polynomial $p(x) = x^{3} - 3x^{2} - 6x + 8$ with the standard form,we have $a = 1$,$b = -3$,$c = -6$,and $d = 8$.Substituting these values into the formula,we get $\alpha \beta \gamma = -\frac{8}{1} = -8$.

If $\alpha, \beta$ and $\gamma$ are the zeros of the cubic polynomial $p(x) = x^{3} - 3x^{2} - 6x + 8$,then $\alpha \beta \gamma = \dots$

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